SOLUTION: P(C)= 0.2 P(B)= 0.3 And Events are Mutually Exclusive.. Find P(BuC')'..

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Question 965984: P(C)= 0.2
P(B)= 0.3
And Events are Mutually Exclusive..
Find P(BuC')'..
Answer by tenkun(12) About Me  (Show Source):
You can put this solution on YOUR website!
P(C)= 0.2
P(B)= 0.3
P(C') = 1-P(C)= 0.8
P(B intersection C')= P(B)*P(C')
=0.3*0.8
= 0.24
P(BuC')= P(B)+P(C')-P(B intersection C')
= 0.3+0.8-0.24
=0.86
P(BuC')'=1 -P(BuC')
=1-0.86
=0.14