SOLUTION: If the horizontal asymptote for f(x) = (x-4)/((x^2)-4) is y=0, why is it that when I plug in x=4 I get y=0 as an answer? I don't understand... What did I do wrong?
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-> SOLUTION: If the horizontal asymptote for f(x) = (x-4)/((x^2)-4) is y=0, why is it that when I plug in x=4 I get y=0 as an answer? I don't understand... What did I do wrong?
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Question 965974: If the horizontal asymptote for f(x) = (x-4)/((x^2)-4) is y=0, why is it that when I plug in x=4 I get y=0 as an answer? I don't understand... What did I do wrong? Answer by josgarithmetic(39618) (Show Source):
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