SOLUTION: Sorry, I had a typo on my previous question. Here is the fixed one:
I was trying to graph f(x) = (x-4)/((x^2)-4) and I stumbled across a problem. Based on the notes I took, the
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-> SOLUTION: Sorry, I had a typo on my previous question. Here is the fixed one:
I was trying to graph f(x) = (x-4)/((x^2)-4) and I stumbled across a problem. Based on the notes I took, the
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Question 965958: Sorry, I had a typo on my previous question. Here is the fixed one:
I was trying to graph f(x) = (x-4)/((x^2)-4) and I stumbled across a problem. Based on the notes I took, the horizontal asymptote would be y=0, since the the degree of the denominator is greater than the degree of the numerator. Yet when I plug in x=4, I get y=0 as an answer. Is there no horizontal asymptote for this equation? Why does y=0 if it's not supposed to? Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Already answered. You made an arithmetic computation mistake; otherwise you found the correct horizontal asymptote.
Typographic mistake? You have enough information to find the answer.
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