SOLUTION: I was trying to graph f(x) = (x-4)/((x^2)-4) and I stumbled across a problem. Based on the notes I took, the horizontal asymptote would be y=0, since the the degree of the denomina

Algebra ->  Rational-functions -> SOLUTION: I was trying to graph f(x) = (x-4)/((x^2)-4) and I stumbled across a problem. Based on the notes I took, the horizontal asymptote would be y=0, since the the degree of the denomina      Log On


   

Question 965956: I was trying to graph f(x) = (x-4)/((x^2)-4) and I stumbled across a problem. Based on the notes I took, the horizontal asymptote would be y=0, since the the degree of the denominator is greater than the degree of the numerator. Yet when I plug in x=0, I get y=0 as an answer. Is there no horizontal asymptote for this equation? Why does y=0 if it's not supposed to?
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
Arithmetic mistake in your finding y=0. Otherwise, your asymptote judgement is good.

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A different view:
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Another view:
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