SOLUTION: There were 3000 people at a football game.some paid $10.00 for their tickets other paid $5.00 the total receipts amounted to #25,00. How many tickets of each kind were sold ?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: There were 3000 people at a football game.some paid $10.00 for their tickets other paid $5.00 the total receipts amounted to #25,00. How many tickets of each kind were sold ?       Log On


   

Question 965796: There were 3000 people at a football game.some paid $10.00 for their tickets other paid $5.00 the total receipts amounted to #25,00. How many tickets of each kind were sold ?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
10T+5F=25,000
T+F=3,000
T=3,000-F
10(3,000-F)+5F=25,000
30,000-10F+5F=25,000
-5F=25,000-30,000
-5F=-5,000
F=-5,000/-5
F=1,000 FIVE DOLLAR TICKETS WERE SOLD
T+1000=3,000
T=3,000-1,000
T=2,000 TEN DOLLAR TICKETS WERE SOLD.
PROOF:
10*2,000+5*1,000=25,000
20,000+5,000=25,000
25,000=25,000