SOLUTION: Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second      Log On


   

Question 965693: Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second
Answer by amarjeeth123(569) About Me  (Show Source):
You can put this solution on YOUR website!
Let the three consecutive odd integers be (x-2),x and (x+2) respectively.
We have (x-2)(x+2)=2x-1
x^2-4=2x-1
x^2-2x-3=0
x^2-3x+x-3=0
x(x-3)+1(x-3)=0
(x+1)(x-3)=0
x=3
The consecutive odd integers are 1,3 and 5 respectively.