SOLUTION: find 2 consecutive numbers such that one-seventh of the smallest exceeds one-eight of the larger by 3.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find 2 consecutive numbers such that one-seventh of the smallest exceeds one-eight of the larger by 3.      Log On


   

Question 965459: find 2 consecutive numbers such that one-seventh of the smallest
exceeds one-eight of the larger by 3.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
n, and n+1.

Check how this equation conforms to the description: n%2F7=%28n%2B1%29%2F8%2B3