SOLUTION: Write an equation in slope-intercept form of a linear function f whose graph satisfies the given conditions. The graph of f passes through (-6, 4) and is perpendicular to the li

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Question 965404: Write an equation in slope-intercept form of a linear function f whose graph satisfies the given conditions.
The graph of f passes through (-6, 4) and is perpendicular to the line that has an x-intercept of 2 and a y–intercept of -4.


Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
perpendicular to the line that has an x-intercept of 2 and a y–intercept of -4.

Negative reciprocal of (1/2) is that described slope.
Meaning, -2=m.

Continuing with point slope form,
y-%28-6%29=-2%28x-4%29
Do what you need to do.....

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

slope-intercept form: y=mx%2Bb where m is a slope and b is y-intercept
given:
the graph of f passes through (-6,+4)
and
is perpendicular to the line that has an x-intercept of 2 and a y–intercept of -4
y=mx%2Bb if (-6,+4) on a line, then we have
4=-6m%2Bb........eq.1
if line is perpendicular to the line that has an x-intercept of 2 and a y–intercept of -4 , then our line has a slope negative reciprocal to the slope of the line that has an x-intercept of 2 and a y–intercept of -4
first find the equation of the line that has an x-intercept of 2 and a y–intercept of -4
if the line that has an x-intercept of 2, then the point (2,0) is on a line
so, we have
0=m%5Bp%5D%2A2%2Bb
0=2m%5Bp%5D%2Bb........... eq.2


if the line that has an y-intercept of -4, then the point (0,-4) is on a line
so, we have
-4=m%5Bp%5D%2A0%2Bb
-4=0%2Bb
b=-4.......substitute in eq.2 and find m%5Bp%5D

0=2m%5Bp%5D-4........... eq.2
2m%5Bp%5D=4
m%5Bp%5D=2

so, the equation of the line is perpendicular to the line that has an x-intercept of 2 and a y–intercept of -4 is
y=2x-4


since the slope is m%5Bp%5D=2, our line will have the slope m=-1%2F2 which is is the negative reciprocal of the m%5Bp%5D=2
so far we have y=-%281%2F2%29x%2Bb and we need to find b
y=2x-4
use 4=-6m%2Bb........eq.1, substitute m=-1%2F2
4=-6%28-%281%2F2%29%29%2Bb
4=cross%286%29%281%2Fcross%282%29%29%2Bb
4=3%2Bb
b=4-3
b=1
so, the equation of a line we are looking for is: y=-%281%2F2%29x%2B1