SOLUTION: Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0

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Question 965388: Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0
2cos%5E2%28x%29-3sinx-3=0
2%281-sin%5E2%28x%29-3sinx-3=0
2-2sin%5E2%28x%29-3sinx-3=0
-2sin%5E2%28x%29-3sinx-1=0
2sin%5E2%28x%29%2B3sinx%2B1=0
(2sinx+1)(sinx+1)=0
sinx=-1/2
no solution, not in domain
or
sinx=-1
no solution, not in domain