SOLUTION: The sides of a square are parallel to the coordinate axes. Its vertices lie on the circle of radius 5 whose center is at the origin. Find coordinates for the four vertices of this

Algebra ->  Length-and-distance -> SOLUTION: The sides of a square are parallel to the coordinate axes. Its vertices lie on the circle of radius 5 whose center is at the origin. Find coordinates for the four vertices of this       Log On


   

Question 965296: The sides of a square are parallel to the coordinate axes. Its vertices lie on the circle of radius 5 whose center is at the origin. Find coordinates for the four vertices of this square.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The square is centered about the origin.
The vertex makes an angle of 45 degrees to the x-axis so it lies on the line y=x
.
.
Substituting,
x%5E2%2By%5E2=25
x%5E2%2Bx%5E2=25
2x%5E2=25
x%5E2=25%2F2
x=5%2Fsqrt%282%29
y=%285sqrt%282%29%29%2F2
So the coordinates are,
(%28+5sqrt%282%29%29%2F2+,%285sqrt%282%29%29%2F2)
(%28-5sqrt%282%29%29%2F2,%285sqrt%282%29%29%2F2)
(%28-5sqrt%282%29%29%2F2,%28-5sqrt%282%29%29%2F2)
(%285sqrt%282%29%29%2F2,%28-5sqrt%282%29%29%2F2)