SOLUTION: I have tried for two days to get the answer to this problem but I have still had no luck.Could you please help me with it and show me how you came to your answer.Thank you so much:

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Question 96528: I have tried for two days to get the answer to this problem but I have still had no luck.Could you please help me with it and show me how you came to your answer.Thank you so much:
The cost for a long-distance telephone call is $0.36 for the first minute and $0.21 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk without exceeding $3.
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose the time for which a person talks be x minutes.
Assume: x > 1

So, the cost is $ 0.36 + $ 0.21(x - 1) = $ (0.21x + 0.15).
This value has to be less than or equal to $ 3.

Hence, 0.21x+%2B+0.15+%3C=+3
0.21x+%3C=+3+-+0.15
0.21x+%3C=+2.85
x+%3C=+2.85%2F0.21
x+%3C=+13.57

As x has to be a positive integer so x = 13.