SOLUTION: pg 125.the cross country teams of East High and West High run against each other twice each fall. At the 1st meet, East's score was 2/3 of West's score. At the 2nd meet, East's sco

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: pg 125.the cross country teams of East High and West High run against each other twice each fall. At the 1st meet, East's score was 2/3 of West's score. At the 2nd meet, East's sco      Log On

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Question 96509This question is from textbook
: pg 125.the cross country teams of East High and West High run against each other twice each fall. At the 1st meet, East's score was 2/3 of West's score. At the 2nd meet, East's score increased by seven points and West's score decreased by seven points. In the 2nd meet West's score was three less than East's score. how many points did each team score in each meet?
I know that...1st meet East = w(2/3) and West = w
2nd meet, East = w(2/3) + 7 and West = w - 7 (AND is 3 less than east) Can you help me set this up? Thank you! This question is from textbook

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
E1=(2/3)W1 ... (3/2)E1=W1 ... E1+7=((3/2)E1-7)+3

E1+4=(3/2)E1-7 ... 11=(1/2)E1 ... 22=E1 ... 33=W1 ... 29=E2 ... 26=W2