SOLUTION: an oil tanker can be emptied by the main pump in 4 hours. an auxiliary pump can empty the tanker in 9 hours. if the main pump is started at 9am when should the auxiliary pump be st

Algebra ->  Rate-of-work-word-problems -> SOLUTION: an oil tanker can be emptied by the main pump in 4 hours. an auxiliary pump can empty the tanker in 9 hours. if the main pump is started at 9am when should the auxiliary pump be st      Log On


   



Question 96503: an oil tanker can be emptied by the main pump in 4 hours. an auxiliary pump can empty the tanker in 9 hours. if the main pump is started at 9am when should the auxiliary pump be started so that the tanker is emptied by noon?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
an oil tanker can be emptied by the main pump in 4 hours. an auxiliary pump can empty the tanker in 9 hours. if the main pump is started at 9am when should the auxiliary pump be started so that the tanker is emptied by noon?
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Main pump DATA:
Time = 4 hr/job ; Rate = 1/4 job/hr
In three hours the main tank can empty (3/4) of the tanker.
(1/4)th of the tanker has to be handled by the auxiliary pump.
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Auxiliary pump DATA:
Time = 9 hrs/job ; Rate = 1/9 job/hr
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EQUATION:
Let "x" be the amount of time the auxiliary tank must be run to
empty (1/4)th of the tanker:
(1/9)x = (3/4)
x = 27/4 = 6 3/4 hrs
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The auxiliary pump should be turned on 6 3/4 hrs before noon, or
at 5:15 AM.
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Cheers,
Stan H.