SOLUTION: write the equation of the line perpendicular to 6x+7y=4 that passes through the point (5,-7)

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Question 965022: write the equation of the line perpendicular to 6x+7y=4 that passes through the point (5,-7)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
7y=-6x%2B4
y=-%286%2F7%29x%2B4%2F7
So,
m%5Bp%5D%2A%28-%286%2F7%29%29=-1
m%5Bp%5D=7%2F6
Use the point-slope form,
y-%28-7%29=%287%2F6%29%28x-5%29
y%2B7=%287%2F6%29%28x-5%29
6y%2B42=7x-35%7D%7D%5D%0D%0A%7B%7B%7B-7x%2B6y=-77
highlight%287x-6y=77%29