SOLUTION: 1. Graph the line y=-3/2x 2. Graph the line y=-4/3x - 4 using only slope and y intercept

Algebra ->  Graphs -> SOLUTION: 1. Graph the line y=-3/2x 2. Graph the line y=-4/3x - 4 using only slope and y intercept       Log On


   

Question 96498: 1. Graph the line y=-3/2x
2. Graph the line y=-4/3x - 4 using only slope and y intercept
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
These explanations are quite long, so here is a table of contents


Problem #1
Problem #2





#1

The equation y=%28-3%2F2%29x really looks like y=%28-3%2F2%29x%2B0

Solved by pluggable solver: Graphing Linear Equations
In order to graph y=%28-3%2F2%29%2Ax%2B0 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-6

y=%28-3%2F2%29%2A%28-6%29%2B0

y=18%2F2%2B0 Multiply

y=18%2F2 Add

y=9 Reduce

So here's one point (-6,9)




Now lets find another point

Plug in x=-4

y=%28-3%2F2%29%2A%28-4%29%2B0

y=12%2F2%2B0 Multiply

y=12%2F2 Add

y=6 Reduce

So here's another point (-4,6). Add this to our graph





Now draw a line through these points

So this is the graph of y=%28-3%2F2%29%2Ax%2B0 through the points (-6,9) and (-4,6)


So from the graph we can see that the slope is -3%2F2 (which tells us that in order to go from point to point we have to start at one point and go down -3 units and to the right 2 units to get to the next point), the y-intercept is (0,0)and the x-intercept is (0,0)


We could graph this equation another way. Since b=0 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,0).


So we have one point (0,0)





Now since the slope is -3%2F2, this means that in order to go from point to point we can use the slope to do so. So starting at (0,0), we can go down 3 units



and to the right 2 units to get to our next point


Now draw a line through those points to graph y=%28-3%2F2%29%2Ax%2B0


So this is the graph of y=%28-3%2F2%29%2Ax%2B0 through the points (0,0) and (2,-3)



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#2


Since b=-+4 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-+4).

So we have one point (0,-+4)



Now since the slope is -4+%2F+3, this means that in order to go from point to point we can use the slope to do so. So starting at (0,-+4), we can go down 4 units


and to the right 3 units to get to our next point

Now draw a line through those points to graph y+=+%28+-+4%2F3+%29+%2A+x-+4

So this is the graph of y+=+%28+-+4%2F3+%29+%2A+x-+4 through the points (0,-4) and (3,-8)

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