SOLUTION: help me out in finding the roots of 3s^4 + 2s^3 + 0.64s^2 + 0.085 - 0.012.
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Question 964899
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help me out in finding the roots of 3s^4 + 2s^3 + 0.64s^2 + 0.085 - 0.012.
Answer by
Fombitz(32388)
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Graphing it, there are two real roots around x=-0.5 and x=0.
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I used Newton's method with those values as starting points.
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