SOLUTION: The length of a rectangle is 4 less than twice the width. The area of the rectangle is 70 square feet. Find the width,w, of the rectangle algebraically. Explain why one of the solu
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Question 964862: The length of a rectangle is 4 less than twice the width. The area of the rectangle is 70 square feet. Find the width,w, of the rectangle algebraically. Explain why one of the solutions for w is not available. Answer by amarjeeth123(570) (Show Source):
You can put this solution on YOUR website! Let the width be x.
Then the length is 2x-4.
Area=Length*width
70=x(2x-4)
x(x-2)=35
x^2-2x-35=0
x^2-7x+5x-35=0
x(x-7)+5(x-7)=0
(x+5)(x-7)=0
x=7 or x=-5
Since the width is positive x=-5 is not possible.
x=7 is the solution.
The width is 7 feet.
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