SOLUTION: two cyclists leave the city at the same time, one going east and the other going west. The westbound cyclist bikes 5mph faster than the eastbound cyclist. after 6 hours they are 24
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Question 96486This question is from textbook Sullivan: College Algebra
: two cyclists leave the city at the same time, one going east and the other going west. The westbound cyclist bikes 5mph faster than the eastbound cyclist. after 6 hours they are 246 miles apart. How fast is each cyclist riding? This question is from textbook Sullivan: College Algebra
You can put this solution on YOUR website! two cyclists leave the city at the same time, one going east and the other going west. The westbound cyclist bikes 5mph faster than the eastbound cyclist. after 6 hours they are 246 miles apart. How fast is each cyclist riding?
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West-bound DATA:
Rate = x+5 mph ; time = 6 hrs. ; distance = 6(x+5) = 6x+30 miles
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East-bound DATA:
Rate = x mph ; time = 6 hrs. ; distance = 6x miles
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EQUATION:
distance + distance = 246 miles
6x+30 + 6x = 246
12x = 216
x = 18 mph (rate of East-bound cyclist)
x+5 = 23 mph (rate of West-bound cyclist)
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Cheers,
Stan H.
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