You can put this solution on YOUR website! Please help me solve the equation.
X'3 + 3x'2 - 4x - 12 =0
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Use ^ (Shift 6) for exponents.
X^3 + 3x^2 - 4x - 12 = 0
Factor by grouping.
Notice that the coeff's of the 2nd 2 terms are -4 times the 1st 2.
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X^3 + 3x^2 - 4x - 12 = x^2*(x-3) - 4*(x-3)
--> (x^2-4)*(x+3) = 0
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x+3 = 0
x = -3
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x^2-4 = 0
x = -2,+2
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