SOLUTION: The quadratic equation is 2x2+6x=4. How do I set it to 0? Do I zero out something? By the way, it is 2X squared +6x=4

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The quadratic equation is 2x2+6x=4. How do I set it to 0? Do I zero out something? By the way, it is 2X squared +6x=4      Log On


   

Question 963800: The quadratic equation is
2x2+6x=4. How do I set it to 0? Do I zero out something?
By the way, it is 2X squared +6x=4
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2%2B6x=4....first simplify;divide both sides by 2
2x%5E2%2F2%2B6x%2F2=4%2F2
x%5E2%2B3x=2
x%5E2%2B3x-2=2-2
x%5E2%2B3x-2=0.....use quadratic formula to solve for x

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-3+%2B-+sqrt%28+3%5E2-4%2A1%2A%28-2%29+%29%29%2F%282%2A1%29+
x+=+%28-3+%2B-+sqrt%28+9%2B8+%29%29%2F2+
x+=+%28-3+%2B-+sqrt%28+17+%29%29%2F2+
x+=+%28-3+%2B-+4.123%29%2F2+
solutions:
x+=+%28-3+%2B+4.123%29%2F2+
x+=+1.123%2F2+
x+=+0.56+
or
x+=+%28-3+-+4.123%29%2F2+
x+=-7.123%2F2+
x+=+-3.56+