SOLUTION: How many real numbers does the quadratic equation have 2x^2+7x+9=I Note use formula x=-b+/- square root b^2-4ac/2a

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Question 963512: How many real numbers does the quadratic equation have 2x^2+7x+9=I
Note use formula x=-b+/- square root b^2-4ac/2a
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

2x%5E2%2B7x%2B9=I
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-7+%2B-+sqrt%28+7%5E2-4%2A2%2A9+%29%29%2F%282%2A2%29+
x+=+%28-7+%2B-+sqrt%28+49-72+%29%29%2F4+
x+=+%28-7+%2B-+sqrt%28+-23+%29%29%2F4+
x+=+%28-7+%2B-+i%2Asqrt%28+23+%29%29%2F4+
solutions:
x+=+%28-7+%2B+i%2Asqrt%28+23+%29%29%2F4+
or
x+=+%28-7+-+i%2Asqrt%28+23+%29%29%2F4+
so, the quadratic equation have 0 real solutions

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+15%2C+2x%5E2%2B7x%2B9%29+