SOLUTION: Part I. G(x) = -x4 + 32x2 +144 a. Show whether G is an even, odd function or neither. If it’s even/odd, identify the property of its graph. (Must show your work) (Help: To sh

Algebra ->  Graphs -> SOLUTION: Part I. G(x) = -x4 + 32x2 +144 a. Show whether G is an even, odd function or neither. If it’s even/odd, identify the property of its graph. (Must show your work) (Help: To sh      Log On


   



Question 963469: Part I.
G(x) = -x4 + 32x2 +144
a. Show whether G is an even, odd function or neither. If it’s even/odd, identify the property of its graph. (Must show your work)
(Help: To show that G is an even function, you must show that G(-x) = G(x), and G is an odd function you must show that G(-x) = -G(x), for ex. F(x) = x3 – 3x is an odd function, since:
F(-x) = (-x)3-3(-x) = -x3+3x = -(x3-3x) = -F(x), thus F is an odd function. And by definition odd function has graph symmetric about the origin).

b. There is a local maximum value of 400 at x = 4, determine the second local maximum value (Use property of the graph of an even/odd function from part a:
(Hints: if (x, f(x)) is a point on the graph of an even function f, then (-x, f(-x)) is symmetric about the y-axis since f(-x)= f(x) is also on the graph of f).

c. Suppose the area under the graph of G between x = 0, and x = 6, that is bounded below by the x-axis is 1612.8 square units, Using the result from part a to determine the area under the graph of G between x = -6 and x = 0, bounded below by the x-axis.
(Hints: Use property of the graph of an even/odd function).
Part II.
a. Choose a library function, then use the library function, and describe how to graph the function:
Y = (x – 3)2 – 5 (just describe without graphing).
(Hints: Y = |x + 4| + 7, then library function is f(x) = |x| absolute value function, then the graph of Y can be obtained from the graph of f by shifting the graph of f to the left 4 units, and up 7 units).

b. Use the library function f(x) =√x Write the function y obtained from f(x) =√x by shifting the graph of f 4 units to the left, and down 2 unit.
(Hints: f(x) = x2; f(x) = x3; f(x) = √x; f(x) = |x|, etc.. each is a library function. If y= f(x-h), then graph of y can be obtained from graph of f by shifting the graph of f to the right h units, etc…Please review transformations of graphs = shifting technique to answer both questions of part a, and b).



Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Part I.
a.
A function is "even" when:
f%28x%29+=+f%28-x%29 for all x
A function is "odd" when:
-f%28x%29+=+f%28-x%29 for all x
check your function: is it "even"
f(x) = f(-x) for all x
G%28-x%29++=++-%28-x%29%5E4%2B32%28-x%29%5E2%2B144...since %28-x%29%5E4 will be same as+%28x%29%5E4, and %28-x%29%5E2 will be same as %28x%29%5E2, we have
G%28-x%29++=++-x%5E4%2B32x%5E2%2B144
so, your function is even
is it odd:
-f%28x%29+=+f%28-x%29 for all x
+-%28+-x%5E4%2B32x%5E2%2B144%29=-%28-x%29%5E4%2B32%28-x%29%5E2%2B144
+x%5E4-32x%5E2-144%3C%3E-x%5E4%2B32x%5E2%2B144.......your function is not odd

b.
There is a local maximum value of 400 at x+=+4, determine the second local maximum value:
(x,+f%28x%29) =(4, 400)
find
G%28-4%29++=++-%28-4%29%5E4%2B32%28-4%29%5E2%2B144
G%28-4%29++=++-256%2B32%2A16%2B144
G%28-4%29++=++-256%2B512%2B144
G%28-4%29++=+400
so, if (4, 400) is a point on the graph of an even function G, then (-4, 400) is symmetric about the y-axis since G%28-x%29=+G%28x%29 is also on the graph of G

c. Suppose the area under the graph of G between x+=+0, and x+=+6, that is bounded below by the x-axis is 1612.8 square units, Using the result from part a to determine the area under the graph of G between x+=+-6 and x+=+0, bounded below by the x-axis.


Graphs of even and odd functions have following properties:
If function is even then its graph is symmetric about y-axis.
If function is odd then its graph is symmetric about origin.
so, because the graph is symmetric about y-axis, the area under the graph of G between x+=+-6 and x+=+0 is bounded below by the x-axis is 1612.8 square units

Part II.
a.
Choose a library function, then use the library function, and describe how to graph the function:
Y+=+%28x-3%29%5E2+-5 (just describe without graphing).
library function is f%28x%29+=x%5E2
and Y can be obtained from the graph of f%28x%29 by shifting the graph of f to the right 3 units, and down 5 units
b.
Use the library function f%28x%29+=sqrt%28x%29 Write the function y obtained from f%28x%29+=sqrt%28x%29 by shifting the graph of f 4 units to the left, and down 2 unit.
f%28x%29+=sqrt%28x%2B4%29+-2