SOLUTION: Lee can ride his bicycle 50 mi in the same time it takes him to drive 125 mi. If his driving rate is 30 mi/h faster than his rate bicycling, find each rate.
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Question 963404: Lee can ride his bicycle 50 mi in the same time it takes him to drive 125 mi. If his driving rate is 30 mi/h faster than his rate bicycling, find each rate. Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! we will find the time it takes him to ride 50 or drive 125 given that he drives 30mph faster than he can pedal.
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We have to begin with the formula
d= r*t (distance = rate * time)Therefore:
r= d/t
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And the problem says that
d/t(b)= d/t(d)-30
50/t = (125/t)-30 Subtract 125/t, both sides:
-75t= -30 Divide both sides by -75 (remember -/- = +)
t= 2.5 This is the time it takes him to bike 50 or drive 125
50/2.5= 20 this is how fast he goes on his bike
125/2.5= 50 is how fast he drives
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Proof: 50(drive)-30= 20(bike) we have the correct answers.
