Question 963400: (Y+5)^2=-4X+28
Whats the directrix, vertex, and focus?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! (Y+5)^2=-4X+28
Whats the directrix, vertex, and focus?
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(y+5)^2=-4(x-7)
This is an equation of a parabola that opens leftward
Its basic equation: (y-k)^2=4p(x-k), (h,k)=coordinates of the vertex
For given equation:
vertex: (7,-5)
4p=4
p=1
axis of symmetry: y=5
focus: (6,-5) (p-distance left of vertex on the axis of symmetry)
directrix: x=8 (p-distance right of vertex on the axis of symmetry)
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