SOLUTION: The wind is blowing an average of 10 mph. riding with the wind the bicyclist can cycle 75 miles in the same amount of time it takes the cyclist 15 miles against this same wind. wha

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Question 963148: The wind is blowing an average of 10 mph. riding with the wind the bicyclist can cycle 75 miles in the same amount of time it takes the cyclist 15 miles against this same wind. what is the bicyclist's average rate in calm air?
Found 2 solutions by ankor@dixie-net.com, Alan3354:
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
The wind is blowing an average of 10 mph. riding with the wind the bicyclist can cycle 75 miles in the same amount of time it takes the cyclist 15 miles against this same wind. what is the bicyclist's average rate in calm air?
:
let s = his rate in calm air
then
(s-10) = effective speed against the wind
and
(s+10) = effective speed with the wind
:
Write a time equation; time = dist/speed
:
=
crosss multiply
75(s-10) = 15(s+10)
75s - 750 = 15s + 150
75s - 15s = 150 + 750
60s = 900
s = 900/60
s = 15 mph, his rate in calm air
:
:
Check this; find the actual time of each, should be equal
75/25 = 3 hrs with the wind
15/5 = 3 hrs against the wind

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
The wind is blowing an average of 10 mph. riding with the wind the bicyclist can cycle 75 miles in the same amount of time it takes the cyclist 15 miles against this same wind. what is the bicyclist's average rate in calm air?
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The effect of wind on a bicyclist is not clearly defined.
The windspeed is not added or subtracted as it is on an airplane.
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A wind at 90 degrees from the heading of the bicycle does not sent the bicycle on a resultant course.
Anyone who has ridden a bicycle knows this.
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People who don't know what they're doing should not write math textbooks.
They should stick to politics.