SOLUTION: The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 54 ft2 . Find the dimensions of the rectangle.

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Question 963133: The length of a rectangle is
3 ft
more than twice the width, and the area of the rectangle is
54 ft2
. Find the dimensions of the rectangle.
Answer by amarjeeth123(569) About Me  (Show Source):
You can put this solution on YOUR website!
Let the width be x feet.
Then the length is 2x+3 feet.
Area of the rectangle is 54 ft2.
Area=length*width
x(2x+3)=54
2x^2+3x-54=0
2x^2+12x-9x-54=0
2x(x+6)-9(x+6)=0
(2x-9)(x+6)=0
x=9/2 is the solution as x cannot be negative.
The width is 4.5 feet.
The length is 12 feet.