SOLUTION: find three consecutive even integers such that the product of the first and second is equal to two less than five times the third number

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Question 963075: find three consecutive even integers such that the product of the first and second is equal to two less than five times the third number
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

(x-2)(x) = 5(x+2) - 2
x^2 - 2x = 5x + 8
x^2 - 7x - 8 = 0
(x - 8)(x + 1) = 0

x is even, so x = 8.

The integers are 6, 8, and 10.