SOLUTION: What is the center of the circle given by the equation x^2 + y^2 - 10x + 14y+ 10 =0

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Question 963056: What is the center of the circle given by the equation x^2 + y^2 - 10x + 14y+ 10 =0
Answer by MathLover1(20850) About Me  (Show Source):
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x%5E2+%2B+y%5E2+-+10x+%2B+14y%2B+10+=0+
%28x%5E2+-10x+%29%2B+%28y%5E2%2B+14y%29=-10 ..............complete square
%28x%5E2+-10x%2B_+%29-_%2B+%28y%5E2%2B+14y%2B_%29-_=-10+
%28x%5E2+-10x%2B5%5E2+%29-5%5E2%2B+%28y%5E2%2B+14y%2B7%5E2%29-7%5E2=-10+
%28x+-+5%29%5E2+-25%2B+%28y%2B7%29%5E2-49=-10
%28x-+5%29%5E2+%2B+%28y%2B7%29%5E2=-10+%2B25%2B49
%28x+-+5%29%5E2+%2B+%28y%2B7%29%5E2=64 => center is at (5,-7) and the radius is sqrt%2864%29=8