SOLUTION: Could you help me in these logarhytmes? 3log^2x-2logx=0 Log3x(3logx-4)+1=0

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Question 962860: Could you help me in these logarhytmes?
3log^2x-2logx=0
Log3x(3logx-4)+1=0
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Could you help me in these logarhytmes [sic]?
It's logarithms.
------------
3log^2x-2logx=0
log(x)*(3log(x) - 2) = 0
log(x) = 0
x = 1
-------------------
3log(x) - 2 = 0
log(x) = 2/3
x+=+10%5E%282%2F3%29
x =~ 4.6416
=============================
Log3x(3logx-4)+1=0
Clarify: log(3x) or log^3(x)