SOLUTION: in a triangle ABC, if Cos A Cos B Cos C= -1/2 and B=C, then C=
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Question 962845
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in a triangle ABC, if Cos A Cos B Cos C= -1/2 and B=C, then C=
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in a triangle ABC, if Cos A Cos B Cos C= -1/2 and B=C, then C=
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Not clear.
Is the product of the cosines = -1/2?