SOLUTION: solve the equation, [0, 2pi) a) cos(pi/2+x)-cos(pi/2-x)=√2

Algebra ->  Trigonometry-basics -> SOLUTION: solve the equation, [0, 2pi) a) cos(pi/2+x)-cos(pi/2-x)=√2      Log On


   

Question 962815: solve the equation, [0, 2pi)
a) cos(pi/2+x)-cos(pi/2-x)=√2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve the equation, [0, 2pi)
a) cos(pi/2+x)-cos(pi/2-x)=√2
(cos(π/2)*cosx-sin(π/2)*sinx-[(cos(π/2)*cosx+sin(π/2)*sinx]=√2
0*cosx-1*sinx-0*cosx-1*sinx=√2
-2sinx=√2
sinx=-√2/2
x=3π/4, 5π/4