SOLUTION: If distance ‘s’ is a function of time ‘t’ given by s = t3 – 6t2 – 15t + 12 then the velocity when acceleration is 0 is

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Question 962807: If distance ‘s’ is a function of time ‘t’ given by s = t3 – 6t2 – 15t + 12 then the velocity when acceleration is 0 is
Answer by amarjeeth123(569) About Me  (Show Source):
You can put this solution on YOUR website!
s = t3 – 6t2 – 15t + 12
Velocity v=ds/dt=3t2-12t-15
Acceleration=dv/dt=6t-12
When acceleration is zero we have 6t-12=0
t=2 sec
Velocity v=3(2)^2-12(2)-15=12-24-15=-27 units