SOLUTION: George has 12 feet of fencing to build a dog pen. He decides to use the side of his garage for one side of the rectangular dog pen. A) find the area of the dog pen if he makes all

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: George has 12 feet of fencing to build a dog pen. He decides to use the side of his garage for one side of the rectangular dog pen. A) find the area of the dog pen if he makes all       Log On

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Question 962691: George has 12 feet of fencing to build a dog pen. He decides to use the side of his garage for one side of the rectangular dog pen. A) find the area of the dog pen if he makes all three sides of the dog pen the same length. B) find the area of the dog pen if he makes the side opposite the garage twice as long as the two other sides. C) find the area of the dog pen if he makes the side opposite the garage one foot longer than one of the two other sides.
Answer by macston(5194) About Me  (Show Source):
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A) 12 feet/3=4 feet Each side would be 4 feet.
A=(4 feet)(4 feet)=16 square feet
ANSWER A): The area with all sides equal is 16 square feet.
B) L=length=side opposite garage=2W: W=width=side adjacent garage
L+2W=12 feet Substitute for L.
2W+2W=12 feet
4W=12 feet
W=3 feet
L=2W=6 feet
Area=(L)(W)=(6 feet)(3 feet)=18 square feet
ANSWER B): The area with side opposite twice as long is 18 square feet.
C) L=length=side opposite garage=W+1: W=width=side adjacent garage
L+2W=12 feet Substitute for L.
(W+1)+2W=12 feet
3W+1=12 feet
3W=11 feet
W=11/3 feet
L=W+1=(11/3 feet)+(3/3 feet)=14/3 feet
Area=(L)(W)=(11/3 feet)(14/3 feet)=154/9 square feet=17.1 square feet
ANSWER C): The area with opposite side 1 foot longer is 17.1 square feet.