Question 962546: Three times the largest of four consecutive odd integers is three less than four times the smallest of the four consecutive odd integers. What is the smallest of the four consecutive odd integers?
My question is what is the right way to set this up? If there is a specific way to set the equation up, how would you solve it?
Thank you for answering!
Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! The four consecutive odd integers are n,n+2,n+4,n+6
3(n+6)=4(n)-3
3n+18=4n-3 Add 3 to each side.
3n+21=4n Subtract 3n from each side.
21=n The smallest number is 21.
CHECK:
n+6=21+6=27 The largest number is 27.
3(27)=4(21)-3
81=84-3
81=81
|
|
|