Question 962541: I am not sure if this is in the right section but the question is:
On Planet X, the height, in meters, of an object, t seconds after being launched from a device, 30 meters above the ground, is given by h(t) = 88t - 11t^2 + 30. At what time(s), in seconds, will the object be 162 meters above ground?
I have gotten to 
However When I try factoring, it works out to a decimal when the answers(here they are for reference, page 24, question 69: http://mohandasmohandas.com/african1/Algebra1finalexam2004.pdf) do not have decimals.
Thank you for answering!
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! Height, h(t) is defined as
h(t) = 88t - 11t^2 + 30
so we substitute 162 for h(t):
162 = 88t - 11t^2 + 30
0 = 88t - 11t^2 - 132
reordering terms:
0 = -11t^2 + 88t - 132
0 = -11t^2 + 22t + 66t - 132
0 = (-11t^2 + 22t) + (66t - 132)
0 = -11t(t - 2) + 66(t - 2)
0 = (t - 2)(-11t+66)
t = {2,6)
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