Question 962516: For the following set of data, find the population variance, to the nearest 10th.
142, 161, 159, 115, 140, 154, 167
Answer by amarjeeth123(570)   (Show Source):
You can put this solution on YOUR website! The set of data is 142, 161, 159, 115, 140, 154, 167.
Mean=142+161+159+115+140+154+167/7=148.285
Distance from the mean for each data point is (142-148.285),(161-148.285),(159-148.285),(115-148.285),(140-148.285),(154-148.285),(167-148.285)
Distance from the mean for each data point is -6.285,12.715,10.715,-33.285,-8.285,5.715,18.715
Variance =((-6.285)^2+(12.715)^2+(10.715)^2+(-33.285)^2+(-8.285)^2+(5.715)^2+(18.715)^2)/7
=(39.501+161.671+114.811+1107.891+68.641+32.661+350.251)/7
=1875.427/7
=267.918
=267.9(rounded off to the 10th)
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