SOLUTION: The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the
Algebra ->
Angles
-> SOLUTION: The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the
Log On
Question 962394: The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the measure of angle B. Find the measure of each angle.
Thank you for your help. It helps me a lot to solve this problem. Found 2 solutions by macston, MathTherapy:Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
.
A=C-20; C=2B
2B=C
B=C/2
A+B+C=180 Substitute for A and B.
(C-20)+(C/2)+C=180
2.5C-20=180 Add 20 to each side.
2.5C=200 Divide each side by 2.5.
C=80 ANSWER 1: Angle C is 80 degrees.
B=C/2=80/2=40 ANSWER 2: Angle B is 40 degrees.
A=C-20=80-20=60 ANSWER 3: Angle A is 60 degrees.
CHECK:
A+B+C=180 degrees
60 degrees+40 degrees+80 degrees=180 degrees
180 degrees=180 degrees
You can put this solution on YOUR website!
The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the measure of angle B. Find the measure of each angle.
Thank you for your help. It helps me a lot to solve this problem.
Let measure of ∠B be B
Then measure of ∠C is: 2B
Measure of ∠A is: 2B - 20
Therefore, we get: B + 2B + 2B - 20 = 180
5B = 200
∠B measures: , or
∠C measures: , or
∠A measures: , or
