SOLUTION: A campus club held a bake sale as a fund-raiser,selling coffee,muffins and bacon-and-egg sandwiches. The club members charged $1 for a cup of coffee, $2 for a muffin, and $3 for a
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Question 962380: A campus club held a bake sale as a fund-raiser,selling coffee,muffins and bacon-and-egg sandwiches. The club members charged $1 for a cup of coffee, $2 for a muffin, and $3 for a bacon-and-egg sandwich. They sold total of 50 items, raising &85 dollars. If the club members sold five more muffins than cup of coffee, how many bacon-and-egg sandwiches did they sell?
Thank you in advance! Answer by hkwu(60) (Show Source):
You can put this solution on YOUR website! Let
c = # of cups of coffee sold
m = # of muffins sold
s = # of sandwiches sold
We know we sold 50 items, so this equation must hold:
We also know that we made $85, so this equation must also hold:
We know that we sold 5 more muffins than coffees, so we know that
If we substitute this, we get
Taking this equation, we substitute once again, this time into the second equation.
We now know that we sold 20 coffees. Since we sold 5 more muffins than coffees, we know we sold 25 muffins. Finally, since we sold 50 items in total, we discover that we sold 5 sandwiches.
