SOLUTION: a jar contains $8.75 in nickels, dimes, and quarters. If there are two times as many dimes as there are nickels, and 10 more dimes than quarters, how many of each coin are in the j

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Question 962207: a jar contains $8.75 in nickels, dimes, and quarters. If there are two times as many dimes as there are nickels, and 10 more dimes than quarters, how many of each coin are in the jar?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
d = number of dimes
q = number of quarters

5n + 10d + 25q = 875
d = 2n
d = q + 10

(substitute second equation)
25n + 25q = 875
2n - q = 10

2n + 2q = 70
-2n + q = -10
----------------------
3q = 60
q = 20 ---> d = 30 ---> n = 15

There are 15 nickels, 30 dimes, and 20 quarters.