SOLUTION: Which is the equation in slope-intercept form for the line that passes through (6, 16) and is perpendicular to 2x + 5y = 4?

Algebra ->  Linear-equations -> SOLUTION: Which is the equation in slope-intercept form for the line that passes through (6, 16) and is perpendicular to 2x + 5y = 4?       Log On


   



Question 961695: Which is the equation in slope-intercept form for the line that passes through (6, 16) and is perpendicular to 2x + 5y = 4?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
5y+=+-2x%2B4
y=-%282%2F5%29x%2B4%2F5
Perpendicular lines have slopes that are negative reciprocals,
m%5Bp%5D%28-%282%2F5%29%29=-1
m%5Bp%5D=5%2F2
Use the point slope form and convert to slope-intercept form,
y-16=%285%2F2%29%28x-6%29
y-16=%285%2F2%29x-15
highlight%28y=%285%2F2%29x%2B1%29
.
.
.
.