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Question 961576: Two sets of three consecutive integers have a property that the product of the larger two is one less than seven times the smallest.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! let the consecutive integers be: x, (x+1), (x+2)
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Two sets of three consecutive integers have a property that the product of the larger two is one less than seven times the smallest.
(x+1)*(x+2) = 7x - 1
FOIL
x^2 + 2x + x + 2 = 7x - 1
x^2 + 3x - 7x + 2 + 1 = 0
x^2 - 4x + 3 = 0
Factors to:
(x-3)(x-1) = 0
two solutions
x = 3; 3, 4, 5 is the 1st set
and
x = 1; 1, 2, 3 is the 2nd set
0 solutions
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