SOLUTION: (sqrt2)(sinx)(cosx)+(cosx)=0 Cosx(sqrt2*sinx+1)=0 cosx(sqrt2*sinx+1)^2=0 Where do I go after this? (besides expanding the parentheses that is being squared)

Algebra ->  Trigonometry-basics -> SOLUTION: (sqrt2)(sinx)(cosx)+(cosx)=0 Cosx(sqrt2*sinx+1)=0 cosx(sqrt2*sinx+1)^2=0 Where do I go after this? (besides expanding the parentheses that is being squared)      Log On


   



Question 961297: (sqrt2)(sinx)(cosx)+(cosx)=0
Cosx(sqrt2*sinx+1)=0
cosx(sqrt2*sinx+1)^2=0
Where do I go after this? (besides expanding the parentheses that is being squared)

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(sqrt2)(sinx)(cosx)+(cosx)=0
Cosx(sqrt2*sinx+1)=0
cosx(sqrt2*sinx+1)^2=0
Where do I go after this? (besides expanding the parentheses that is being squared)
----------------
cosx(sqrt(2)*sinx+1)=0
cosx(sqrt2*sinx+1)^2=0 ************** There's no reason to square it.
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cosx(sqrt(2)*sinx+1)=0
cos(x) = 0
x = pi/2 + n*pi n = 0,1,2,3...
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sinx+1=0
sin(x) = -1
x = 3pi/2 + 2n*pi n = 0,1,2,3...