SOLUTION: How do I write a slope-intercept for a line passing throught the given point that is parallel to the given line (7,-3); 8+7y=4? How do I write a second equation that's perpendicula

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Question 961280: How do I write a slope-intercept for a line passing throught the given point that is parallel to the given line (7,-3); 8+7y=4? How do I write a second equation that's perpendicular tothe given line?
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Familiarize yourself with standard form and slope-intercept form.

7x-8y=7%2A7-8%2A%28-3%29





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assumed you meant the equation to be 8x+7y=4

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do I write a slope-intercept for a line passing throught the given point that is parallel to the given line (7,-3); 8x+7y=4?
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That equation has slope = -8/7
Form:: y = mx + b
Solve for "b"::
-3 = (-8/7)7 + b
b = 5
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Equation:
y = (-8/7)x+5
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How do I write a second equation that's perpendicular to the given line?
slope you want is +7/8
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Form:: y = mx + b
Solve for "b"::
-3 = (7/8)7 + b
-24/8 = 49/8 + b
b = -73/8
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Equation:
y = (7/8)x-(73/8)
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Cheers,
Stan H.
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