Question 961119: in an isosceles triangle the measure of each of equal sides is 10 cm and the angle between them is 45 degree the area of triangle is
Answer by CJKiller3(2)   (Show Source):
You can put this solution on YOUR website! The area of the triangle is 43.5 cm^2. You would have to find the height of the triangle, which you would use h=sqrt(s^2-1/4*b^2) and then you would get approximately 8.7 cm which you plug into the area of a right triangle, since half of an isosceles triangle is a right triangle, which you then would not divide by two in the equation, since you would get the same answer if you did and added it to the other half, because you would get your answer, which is 43.5 cm^2.
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