SOLUTION: If a student wants to mix a 45% acid solution with a 70% acid solution to create a 20 liter 60% acid solution, how many liters of 45% acid should they use?

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Question 960987: If a student wants to mix a 45% acid solution with a 70% acid solution to create a 20 liter 60% acid solution, how many liters of 45% acid should they use?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 45% solution needed
Let +b+ = liters of 70% solution needed
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(1) +a+%2B+b+=+20+
(2) +%28+.45a+%2B+.7b+%29+%2F+20+=+.6++
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(2) +.45a+%2B+.7b+=+12+
(2) +45a+%2B+70b+=+1200+
Multiply both sides of (1) by +45+
and subtract (1) from (2)
(2) +45a+%2B+70b+=+1200+
(1) +-45a+-+45b+=+-900+
---------------------------
+25b+=+300+
+b+=+12+
and
(1) +a+%2B+12+=+20+
(1) +a+=+8+
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8 liters of 45% solution are needed
check:
(2) +%28+.45a+%2B+.7b+%29+%2F+20+=+.6++
(2) +%28+.45%2A8+%2B+.7%2A12+%29+%2F+20+=+.6++
You can finish this