SOLUTION: juan drives to work. because of traffic conditiond, he averages 22 miles per hour. he returns home averaging 32 miles per hour. the total travel time is 2 and 1/4 hours.
a. defi
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: juan drives to work. because of traffic conditiond, he averages 22 miles per hour. he returns home averaging 32 miles per hour. the total travel time is 2 and 1/4 hours.
a. defi
Log On
Question 96088This question is from textbook prentice hall mathematics algebra 1
: juan drives to work. because of traffic conditiond, he averages 22 miles per hour. he returns home averaging 32 miles per hour. the total travel time is 2 and 1/4 hours.
a. define a variable for the time juan takes to work. write an expression for the time juan takes to return home.
b. write and solve an equation to find the time juan spends driving to work.
I attempted to solve this problem and it was a mess. I don't understand how to solve this problem at all. Could someone explain it to me in depth please?
Thanks! This question is from textbook prentice hall mathematics algebra 1
You can put this solution on YOUR website! juan drives to work. because of traffic conditions, he averages 22 miles per hour. he returns home averaging 32 miles per hour. the total travel time is 2 and 1/4 hours.
a. define a variable for the time juan takes to work.
Let t = time to work
:
"write an expression for the time juan takes to return home."
It says the total time for the round trip is 2.25 hrs, therefore
(2.25 - t) = time to return home
:
b. write and solve an equation to find the time juan spends driving to work.
:
We know the distance to and from his work are equal so we can write a distance
equation: Distance = speed * time
:
22t = 32(2.25-t)
22t = 72 - 32t
22t + 32t = 72
54t = 72
t = 72/54
t = 1 hrs, time to work
:
:
Check our solution by finding if the distances are equal, (in decimals on a calculator)
22 * 1.33 = 29.3 miles
32(2.25 - 1.33) = 29.4 miles,
:
Did this make sense to you? Any questions?
