SOLUTION: Use the remainder theorem to find P(-2) for P(x)= x^3+4x^2-4x-8. Specifically give the quotient and the remainder for the associated division and the value of P(-2). Quotient =

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Use the remainder theorem to find P(-2) for P(x)= x^3+4x^2-4x-8. Specifically give the quotient and the remainder for the associated division and the value of P(-2). Quotient =       Log On


   



Question 960772: Use the remainder theorem to find P(-2) for P(x)= x^3+4x^2-4x-8. Specifically give the quotient and the remainder for the associated division and the value of P(-2).
Quotient =
Remainder =
P(-2)=

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Perform synthetic division using that given "root" of -2. The remainder will be P(-2). That is the meaning of the Remainder Theorem.

You should find that the remainder is 8;
therefore P(-2)=8.


-2_____|_____1_____4_____-4______-8
_______|
_______|__________-2____-4_______16
____________________________________
_______|_____1______2_____-8______8


The quotient part without the remainder is x%5E2%2B2x-8.