SOLUTION: Conjugate Zeros Theorem Verify that the indicated complex number is a zero of the given polynomial function f. 1 + i; f(x) = 12x^4 − 23x^3 + 21x^2 + 4x − 2 Use

Algebra ->  Trigonometry-basics -> SOLUTION: Conjugate Zeros Theorem Verify that the indicated complex number is a zero of the given polynomial function f. 1 + i; f(x) = 12x^4 − 23x^3 + 21x^2 + 4x − 2 Use       Log On


   



Question 960679: Conjugate Zeros Theorem
Verify that the indicated complex number is a zero of the given polynomial function f.
1 + i; f(x) = 12x^4 − 23x^3 + 21x^2 + 4x − 2
Use the conjugate zeros theorem and long division to find all other zeros.


Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
A quadratic factor of f(x) is %28x-%281-i%29%29%28x-%281%2Bi%29%29=%28%28x-1%29%2Bi%29%28%28x-1%29-i%29=x%5E2-2x%2B1-i%5E2
x%5E2-2x%2B2.

What happens when you divide 12x%5E4-23x%5E3%2B21x%5E2%2B4x-2 by x%5E2-2x%2B2? Remainder should be 0.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Conjugate Zeros Theorem states:
if 1+%2B+i is zero, then 1+-+i is zero too
so, the product %281+%2B+i%29%281+-+i%29=1%5E2-i%5E2=1-%28-1%29=1%2B1=2 is a factor of
f%28x%29+=+12x%5E4+-23x%5E3+%2B+21x%5E2+%2B+4x+-2 ......so,divide by 2
f%28x%29+=+%2812x%5E4-23x%5E3+%2B+21x%5E2+%2B+4x+-2%29%2F2
f%28x%29+=++%281%2F2%29%2812x%5E4+-23x%5E3+%2B+21x%5E2+%2B+4x+-2%29.......factor %2812x%5E4+-23x%5E3+%2B+21x%5E2+%2B+4x+-2%29
f%28x%29+=+%281%2F2%29%2812x%5E4+-24x%5E3+%2Bx%5E3%2B+24x%5E2+-2x%5E2%2B+2x+-x%5E2%2B2x-2%29......group





f%28x%29+=%281%2F2%29+%2812x%5E2%2B4x-3x-1%29+%28x%5E2-2x%2B2%29
f%28x%29+=%281%2F2%29+%28%2812x%5E2%2B4x%29-%283x%2B1%29%29+%28x%5E2-2x%2B2%29
f%28x%29+=%281%2F2%29+%284x%283x%2B1%29-%283x%2B1%29%29+%28x%5E2-2x%2B2%29
f%28x%29+=%281%2F2%29+%284x-1%29+%283x%2B1%29+%28x%5E2-2x%2B2%29
zeros:
%284x-1%29+=0 =>highlight%28x=1%2F4%29+
%283x%2B1%29=0 =>highlight%28x=-1%2F3%29

x%5E2-2x%2B2=0+=>use quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A2+%29%29%2F%282%2A1%29+

x+=+%282+%2B-+sqrt%28+4-8+%29%29%2F2+
x+=+%282+%2B-+sqrt%28+-4+%29%29%2F2+
x+=+%282+%2B-+2i%29%2F2+
x+=+%281+%2B-+i%29+

=>highlight%28x+=+1%2Bi%29 and highlight%28x+=+1-i%29