SOLUTION: P=I^2(20) represents power in a DC circuit with a resistance of 20 ohms, P is the power (in Watts), and I (in amps) is the current. (Note: This relationship is of the same form

Algebra ->  Coordinate-system -> SOLUTION: P=I^2(20) represents power in a DC circuit with a resistance of 20 ohms, P is the power (in Watts), and I (in amps) is the current. (Note: This relationship is of the same form       Log On


   



Question 960674: P=I^2(20) represents power in a DC circuit with a resistance of 20 ohms, P is the power (in Watts), and I (in amps) is the current.
(Note: This relationship is of the same form as many of the quadratics you will see in this chapter in particular y=x^2(20). As a result the methods you use to solve similar quadratics would apply here.)
If the power is 168.2 Watts what is the current?

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
P=Power (in watts); R=resistance (in ohms)=20 ohms; I=current (in amps)
If the power is 168.2 Watts what is the current?
P=I%5E2R
P%2FR=I%5E2
sqrt%28P%2FR%29=I
sqrt%28168.2%2F20%29=I
sqrt%288.41%29=I
2.9=I ANSWER: The current is 2.9 amps.