SOLUTION: Find an equation for the line with the given properties. Express the equation in slope-intercept form. P=(-5,-4) and Q=(-3,-1)

Algebra ->  Linear-equations -> SOLUTION: Find an equation for the line with the given properties. Express the equation in slope-intercept form. P=(-5,-4) and Q=(-3,-1)      Log On


   

Question 960630: Find an equation for the line with the given properties. Express the equation in slope-intercept form. P=(-5,-4) and Q=(-3,-1)
Answer by MathLover1(20849) About Me  (Show Source):
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Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-5, -4) and (x2, y2) = (-3, -1).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-1--4%29%2F%28-3--5%29+=+1.5.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 1.5%2A-5+%2Bb+=+3.5. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-4-1.5%2A-5+=+3.5.

y=(1.5)x + (3.5)

Your graph:





so, the equation in slope-intercept form is: y=1.5x+%2B+3.5